Patrick's Problems
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Jack Eike's Problems
First, since we know that the parallel lines make the segments proportional, we have to set up a proportion.
x+4 over 3 and x+5 over 6
When you cross multiply, you will end up with 3x+15=6x+24.
So then we subtract 15 from 24 and subtract 6x from 3x.
Now we have -3x=9 and then we divide by -3 to get x=-3
x+4 over 3 and x+5 over 6
When you cross multiply, you will end up with 3x+15=6x+24.
So then we subtract 15 from 24 and subtract 6x from 3x.
Now we have -3x=9 and then we divide by -3 to get x=-3
Since we are dealing with right triangles, we can use trigonometric functions to find missing variables. First, we see that we have an opposite and a missing adjacent. So that would be tangent that we would use to find it. Now we have the tan of 65=1500/x
and when we rearrange the terms we get x=1500/tan of 65. We solve it to 699.461.
and when we rearrange the terms we get x=1500/tan of 65. We solve it to 699.461.
Hannah Lee's Practice Problems
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